Answer
$\color{blue}{y=\frac{3}{4}x+6}$
Work Step by Step
RECALL:
The slope-intercept form of a line's equation is $y=mx+b$ where $m$=slope and $(0, b)$ is the line's y-intercept.
The given line has a slope of $\frac{3}{4}$ therefore the tentative equation of the line is $y=\frac{3}{4}x+b$
To find the value of $b$, substitute the x and y values of the given point into the tentative equation above to obtain:
$y=\frac{3}{4}x+b
\\3=\frac{3}{4}(-4)+b
\\3=-3+b
\\3+3=-3+b+3
\\6=b$
Therefore, the equation of the line is $\color{blue}{y=\frac{3}{4}x+6}$.