## Precalculus (6th Edition)

$\color{blue}{y=\frac{3}{4}x+6}$
RECALL: The slope-intercept form of a line's equation is $y=mx+b$ where $m$=slope and $(0, b)$ is the line's y-intercept. The given line has a slope of $\frac{3}{4}$ therefore the tentative equation of the line is $y=\frac{3}{4}x+b$ To find the value of $b$, substitute the x and y values of the given point into the tentative equation above to obtain: $y=\frac{3}{4}x+b \\3=\frac{3}{4}(-4)+b \\3=-3+b \\3+3=-3+b+3 \\6=b$ Therefore, the equation of the line is $\color{blue}{y=\frac{3}{4}x+6}$.