#### Answer

$\color{blue}{y-5=-4(x+2)}$

#### Work Step by Step

RECALL:
The point-slope form of a line's equation is $y-y_1=m(x-x_1)$ where $m$=slope and $(x_1, y_1)$ is a point on the line.
The given line has a slope of $-4$ and contains the point $(-2, 5)$.
Substitute these into the point-slope form above to obtain:
$y-5 = -4(x-(-2))
\\\color{blue}{y-5=-4(x+2)}$