## Precalculus (6th Edition)

$\color{blue}{y-5=-4(x+2)}$
RECALL: The point-slope form of a line's equation is $y-y_1=m(x-x_1)$ where $m$=slope and $(x_1, y_1)$ is a point on the line. The given line has a slope of $-4$ and contains the point $(-2, 5)$. Substitute these into the point-slope form above to obtain: $y-5 = -4(x-(-2)) \\\color{blue}{y-5=-4(x+2)}$