Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 10 - Analytic Geometry - Test - Page 1003: 12

Answer

See graph, domain $(-\infty,-2]\cup[2,\infty)$, range $(-\infty,\infty)$, asymptotes $y=\pm \frac{3}{2}x$

Work Step by Step

1. Rewrite the given equation as $\frac{x^2}{4}-\frac{y^2}{9}=1$, we have $a=2, b=3$ 2. We can find the domain as $(-\infty,-2]\cup[2,\infty)$, range as $(-\infty,\infty)$. 3. The equations of the asymptotes can be found as $y=\pm \frac{3}{2}x$ 4. See graph.
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