Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 10 - Analytic Geometry - Test - Page 1003: 10

Answer

$\frac{x^2}{400}+\frac{y^2}{144}=1$, $10.4\ ft$

Work Step by Step

1. Start from the standard equation $\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$. Based on the given information, we have $2a=40, a=20$ and $b=12$. Thus the equation is $\frac{x^2}{400}+\frac{y^2}{144}=1$. 2. Let $x=10\ ft$, use it in the equation, we have $\frac{10^2}{400}+\frac{y^2}{144}=1$, thus $y^2=144(1-0.25)\approx10.4\ ft$
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