Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 10 - Analytic Geometry - Test - Page 1003: 9

Answer

$\frac{x^2}{9}+\frac{y^2}{4}=1$.

Work Step by Step

Start from the standard equation $\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$. Based on the given conditions, we have $2a=6, a=3$ and $2b=4, b=4$. Thus the equation is $\frac{x^2}{9}+\frac{y^2}{4}=1$.
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