Answer
domain $(-\infty,\infty)$, range $(-\infty,9)$,
vertex $(3,9)$, axis of symmetry as $x=3$,
See graph.
Work Step by Step
1. Rewrite the equation as $y=-(x^2-6x+9)+9=-(x-3)^2+9$
2. We can identify its domain as $(-\infty,\infty)$, range as $(-\infty,9)$
3. We can find its vertex at $(3,9)$ and axis of symmetry as $x=3$
4. See graph.
