Answer
focus $(\frac{1}{32},0)$, directrix $x=-\frac{1}{32}$
Work Step by Step
1. Rewrite the equation as $y^2=\frac{1}{8}x$, we have $p=\frac{1}{32}$ and the parabola opens right.
2. We can find its vertex at $(0,0)$, focus at $(\frac{1}{32},0)$ and directrix as $x=-\frac{1}{32}$
