Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 10 - Analytic Geometry - Test - Page 1004: 13

Answer

$\frac{y^2}{25}-\frac{x^2}{11}=1$

Work Step by Step

1. From the given conditions, start from the standard equation $\frac{y^2}{b^2}-\frac{x^2}{a^2}=1$ 2. We have $b=5, c=6$, thus $a^2=c^2-b^2=11$ 3. The equation is $\frac{y^2}{25}-\frac{x^2}{11}=1$
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