Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 10 - Analytic Geometry - Test - Page 1004: 20

Answer

$y_1=7\sqrt {\frac{x^2}{25}-1}$, $y_2=-7\sqrt {\frac{x^2}{25}-1}$

Work Step by Step

1. Rewrite the equation as $y^2=49(\frac{x^2}{25}-1)$ or $y=\pm7\sqrt {\frac{x^2}{25}-1}$ 2. We can identify the blue curve as $y_1=7\sqrt {\frac{x^2}{25}-1}$ 3. We can identify the red curve as $y_2=-7\sqrt {\frac{x^2}{25}-1}$
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