Answer
$$\eqalign{
& {\text{domain: }}\left[ { - 4,4} \right] \cr
& {\text{range: }}\left[ { - 2,2} \right] \cr
& {\text{Vertices: }}\left( { \pm 4,0} \right) \cr} $$
Work Step by Step
$$\eqalign{
& \frac{{{x^2}}}{{16}} + \frac{{{y^2}}}{4} = 1 \cr
& {\text{The equation of the ellipse is in the form }}\frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} = 1\,\,\left( {a > b} \right) \cr
& a = 4,\,\,b = 2 \cr
& \cr
& {\text{The ellipse with center at the origin}} \cr
& {\text{Vertices }}\left( { \pm a,0} \right) \cr
& {\text{Vertices }}\left( { \pm 4,0} \right) \cr
& \cr
& {\text{The domain of the ellipse is }}\left[ { - a,a} \right] \cr
& {\text{domain }}\left[ { - 4,4} \right] \cr
& \cr
& {\text{The range of the ellipse is }}\left[ { - b,b} \right] \cr
& {\text{range }}\left[ { - 2,2} \right] \cr
& \cr
& {\text{Therefore,}} \cr
& {\text{domain: }}\left[ { - 4,4} \right] \cr
& {\text{range: }}\left[ { - 2,2} \right] \cr
& {\text{Vertices: }}\left( { \pm 4,0} \right) \cr
& \cr
& {\text{Graph}} \cr} $$
