Chapter 10 - Analytic Geometry - Chapter 10 Test Prep - Review Exercises - Page 1001: 27

$$\eqalign{ & {\text{domain: }}\left[ { - 2,2} \right] \cr & {\text{range: }}\left[ { - 3,3} \right] \cr & {\text{Vertices: }}\left( {0, \pm 3} \right) \cr} $$

$$\eqalign{ & \frac{{{x^2}}}{4} + \frac{{{y^2}}}{9} = 1 \cr & {\text{The equation of the ellipse is in the form }}\frac{{{x^2}}}{{{b^2}}} + \frac{{{y^2}}}{{{a^2}}} = 1\,\,\left( {a > b} \right) \cr & a = 3,\,\,b = 2 \cr & \cr & {\text{The ellipse with center at the origin}} \cr & {\text{Vertices }}\left( {0, \pm a} \right) \cr & {\text{Vertices }}\left( {0, \pm 3} \right) \cr & \cr & {\text{The domain of the ellipse is }}\left[ { - b,b} \right] \cr & {\text{domain }}\left[ { - 2,2} \right] \cr & \cr & {\text{The range of the ellipse is }}\left[ { - a,a} \right] \cr & {\text{range }}\left[ { - 3,3} \right] \cr & \cr & \cr & {\text{Therefore,}} \cr & {\text{domain: }}\left[ { - 2,2} \right] \cr & {\text{range: }}\left[ { - 3,3} \right] \cr & {\text{Vertices: }}\left( {0, \pm 3} \right) \cr & \cr & {\text{Graph}} \cr} $$