#### Answer

The solution set is $\left\{2, 6\right\}$.

#### Work Step by Step

Subtract $8x-12$ to both sides of the equation to obtain:
$x^2-(8x-12) = 8x-12-(8x-12)
\\x^2-8x+12=0$
Factor the trinomial to obtain:
$(x-6)(x-2)=0$
Use the Zero-Factor Property by equating each factor to zero, then solve each equation to obtain:
\begin{array}{ccc}
&x-6 &\text{or} &x-2=0
\\&x=6 &\text{or} &x=2
\end{array}
Thus, the solution set is $\left\{2, 6\right\}$.