## Precalculus (6th Edition)

$x=\dfrac{15}{7}$
Simplify starting with the innermost part of the grouping symbols to obtain: $$3[2x-6-(-2x)+1]=5x \\3[2x-6+2x+1]=5x \\3[4x-5]=5x$$ Distribute $3$ to obtain: $$3(4x)-3(5)=5x \\12x-15=5x$$ Subtract $5x$ and add $15$ to both sides of the equation to obtain: $$12x-15-5x+15=5x-5x+15 \\7x=15$$ Divide $7$ to both sides to obtain: $$\dfrac{7x}{7}=\dfrac{15}{7} \\x=\dfrac{15}{7}$$