## Precalculus (6th Edition)

$x=-1$
Distribute $2$: $5-(6x+3)=2(2)-2(2x) \\5-(6x+3) = 4-4x$ Subtract each term of the binomial to obtain: $5-6x-3=4-4x \\-6x+2=4-4x$ Add $6x$ and subtract $4$ to both sides of the equation to obtain: $-6x+2+6x-4=4-4x+6x-4 \\-2=2x$ Divide $2$ to both sides to obtain: $\dfrac{-2}{2}=\dfrac{2x}{2} \\-1 = x$