#### Answer

$\color{blue}{\left\{x|x \ne 3\right\}}$

#### Work Step by Step

The value of $x$ cannot be $3$ as it will make the denominator zero.
Since any quantity is equal to itself, then the given equation is an identity.
Thus, the value of $x$ can be any number except $3$.
Therefore, the solution set is: $\color{blue}{\left\{x|x \ne 3\right\}}$.