## Precalculus (6th Edition)

$\color{blue}{\left\{x|x \ne 3\right\}}$
The value of $x$ cannot be $3$ as it will make the denominator zero. Since any quantity is equal to itself, then the given equation is an identity. Thus, the value of $x$ can be any number except $3$. Therefore, the solution set is: $\color{blue}{\left\{x|x \ne 3\right\}}$.