Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - Summary Exercises on Solving Equations - Exercises - Page 149: 22


$a = \pm \sqrt{c^2-b^2}$

Work Step by Step

Subtract $b^2$ to both side of the equation to obtain: $$a^2+b^2-b^2=c^2-b^2 \\a^2=c^2-b^2$$ Take the square root of both sides of the equation to obtain: $$\sqrt{a^2}=\pm \sqrt{c^2-b^2} \\a = \pm \sqrt{c^2-b^2}$$
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