Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - Summary Exercises on Solving Equations - Exercises - Page 149: 15



Work Step by Step

Cube both sides to obtain: $$(\sqrt[3]{2x+1})^3=(\sqrt[3]{9})^3 \\2x+1=9$$ Subtract $1$ to both sides: $$2x+1-1=9-1 \\2x=8$$ Divide $2$ to both sides: $$\dfrac{2x}{2}=\dfrac{8}{2} \\x=4$$
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