## Precalculus (6th Edition)

Published by Pearson

# Chapter 1 - Equations and Inequalities - 1.3 Complex Numbers - 1.3 Exercises - Page 111: 8

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#### Work Step by Step

Note that $i^{12}=(i^2)^6$. Thus, the given expression is equivalent to: $=(i^2)^{6}$ With $i-\sqrt{-1}$. the expression above simplifies to: $=[(\sqrt{-1})^2]^6 \\=(-1)^6 \\=1$ Therefore the given statement is true.

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