## Precalculus (6th Edition)

Note that $i^{12}=(i^2)^6$. Thus, the given expression is equivalent to: $=(i^2)^{6}$ With $i-\sqrt{-1}$. the expression above simplifies to: $=[(\sqrt{-1})^2]^6 \\=(-1)^6 \\=1$ Therefore the given statement is true.