Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.3 Complex Numbers - 1.3 Exercises - Page 111: 10



Work Step by Step

Square the binomial using the formula $(a+b)^2=a^2+2ab+b^2$ to obtain: $(5+3i)^2 \\=5^2 + 2(5)(3i) + (3i)^2 \\=25 + 30i + 9i^2$ With $\sqrt{-1}=i$, the given expression simplifies to: $=25+30i+9(\sqrt{-1})^2 \\=25+30i+9(-1) \\=25+30i-9 \\=16+30i$ The expression above is not equal to the expression on the right side of the given equation. Thus, the given statement is false.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.