Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.3 Complex Numbers - 1.3 Exercises: 20

Answer

pure imaginary number; nonreal complex number; complex number

Work Step by Step

Simplify the given expression to obtain: $=\sqrt{36(-1)} \\=6\sqrt{-1} \\=6i$ RECALL: The complex number $a+bi$ is: (i) a pure imaginary number when $a=0$ and $b\ne0$; (ii) a real number when $b=0$; (iii) a nonreal complex number when $b\ne0$. The given expression is equivalent to $6i$. $6i$ has $a=0$ and $b\ne0$. Thus, it is a: pure imaginary number; nonreal complex number; complex number
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