Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.3 Complex Numbers - 1.3 Exercises - Page 111: 1


$\sqrt{-1}$; $-1$

Work Step by Step

RECALL: $i=\sqrt{-1}$ Thus, $i^2=(\sqrt{-1})^2=-1$ Therefore, the missing expressions in the given statement are (in order): $\sqrt{-1}$; $-1$
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