Answer
$\sqrt{-1}$;
$-1$
Work Step by Step
RECALL:
$i=\sqrt{-1}$
Thus,
$i^2=(\sqrt{-1})^2=-1$
Therefore, the missing expressions in the given statement are (in order):
$\sqrt{-1}$; $-1$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 1 - Equations and Inequalities - 1.3 Complex Numbers - 1.3 Exercises - Page 111: 1
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