Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.3 Complex Numbers - 1.3 Exercises - Page 111: 7


The statement given is false. A true statement would be: $\sqrt{-4}\cdot\sqrt{-9}=6$

Work Step by Step

$\sqrt{-4}\cdot\sqrt{-9}=-6$ Evaluate the product on the left side and simplify: $\sqrt{(-4)(-9)}=-6$ $\sqrt{36}=-6$ $6\ne-6$ False A true statement would be: $\sqrt{-4}\cdot\sqrt{-9}=6$
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