## Precalculus (6th Edition)

Published by Pearson

# Chapter 1 - Equations and Inequalities - 1.3 Complex Numbers - 1.3 Exercises: 25

#### Answer

$12i\sqrt2$

#### Work Step by Step

Factor the radicand so that one factor is a perfect square then simplify to obtain: $=\sqrt{144(-2)} \\=\sqrt{12^2(-2)} \\=12\sqrt{-2}$ Factor out $-1$ in the radicand to obtain: $=12\sqrt{-1(2)}$ Since $\sqrt{-1} = i$, bring out the square root of $-1$, which is $i$, to obtain: $=12i\sqrt2$

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