Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.9 - Linear Inequalities and Absolute Value Inequalities - Exercise Set - Page 140: 144

Answer

See below:
1574313629

Work Step by Step

Consider the equation $y=4-{{x}^{2}}$. Substitute $x=-3$ and solve: $\begin{align} & y=4-{{x}^{2}} \\ & =4-{{\left( -3 \right)}^{2}} \\ & =4-9 \\ & =-5 \end{align}$ Substitute $x=-2$ and solve: $\begin{align} & y=4-{{x}^{2}} \\ & =4-{{\left( -2 \right)}^{2}} \\ & =4-4 \\ & =0 \end{align}$ Substitute $x=-1$ and solve: $\begin{align} & y=4-{{x}^{2}} \\ & =4-{{\left( -1 \right)}^{2}} \\ & =4-1 \\ & =3 \end{align}$ Substitute $x=0$ and solve: $\begin{align} & y=4-{{x}^{2}} \\ & =4-{{0}^{2}} \\ & =4-0 \\ & =4 \end{align}$ Substitute $x=1$ and solve: $\begin{align} & y=4-{{x}^{2}} \\ & =4-{{1}^{2}} \\ & =4-1 \\ & =3 \end{align}$ Substitute $x=2$ and solve: $\begin{align} & y=4-{{x}^{2}} \\ & =4-{{2}^{2}} \\ & =4-4 \\ & =0 \end{align}$ Substitute $x=3$ and solve: $\begin{align} & y=4-{{x}^{2}} \\ & =4-{{3}^{2}} \\ & =4-9 \\ & =-5 \end{align}$
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