## Precalculus (6th Edition) Blitzer

The highest number of bags is 29. $x \leq 29$
First, let $x$ be the number of bags we can lift in one trip safely. Then from the asked problem we have inequality: $3000 - (245 + 95x) \geq 0$ Next, all we have to do is solve the inequality. $3000 - (245 + 95x) \geq 0$ $3000 - 245 - 95x \geq 0$ Add $95x$ on both sides. $2755- 95x + 95x \geq 0 + 95x$ $2755 \geq 95x$ Divide with $95$ on both sides. $\frac{2755}{95} \geq \frac{95}{95}x$ $29 \geq x$ or we can also write: $x \leq 29$ Which is our solution.