Answer
The highest number of bags is 29.
$ x \leq 29$
Work Step by Step
First, let $x$ be the number of bags we can lift in one trip safely.
Then from the asked problem we have inequality:
$ 3000 - (245 + 95x) \geq 0$
Next, all we have to do is solve the inequality.
$ 3000 - (245 + 95x) \geq 0$
$ 3000 - 245 - 95x \geq 0$
Add $95x$ on both sides.
$ 2755- 95x + 95x \geq 0 + 95x$
$ 2755 \geq 95x$
Divide with $95$ on both sides.
$ \frac{2755}{95} \geq \frac{95}{95}x$
$ 29 \geq x$
or we can also write:
$ x \leq 29$
Which is our solution.
