Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.9 - Linear Inequalities and Absolute Value Inequalities - Exercise Set - Page 140: 118

Answer

The highest is $39$ bags. $x \leq 39$

Work Step by Step

First, let $x$ be the number of bags we can lift in one trip safely Then from the asked problem we have the inequality: $ 2800 - (265 + 65x) \geq 0$ Next, all we have to do is solve the inequality. $ 2800 - (265 + 65x) \geq 0$ $ 2800 - 265 - 65x \geq 0$ Add $65x$ on both sides. $ 2535- 65x + 65x \geq 0 + 65x$ $ 2535 \geq 65x$ Divide with $65$ on both sides. $ \frac{2535}{65} \geq \frac{65}{65}x$ $ 39 \geq x$ or we can also write: $ x \leq 39$ Which is our solution.
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