## Precalculus (6th Edition) Blitzer

The highest is $39$ bags. $x \leq 39$
First, let $x$ be the number of bags we can lift in one trip safely Then from the asked problem we have the inequality: $2800 - (265 + 65x) \geq 0$ Next, all we have to do is solve the inequality. $2800 - (265 + 65x) \geq 0$ $2800 - 265 - 65x \geq 0$ Add $65x$ on both sides. $2535- 65x + 65x \geq 0 + 65x$ $2535 \geq 65x$ Divide with $65$ on both sides. $\frac{2535}{65} \geq \frac{65}{65}x$ $39 \geq x$ or we can also write: $x \leq 39$ Which is our solution.