## Precalculus (6th Edition) Blitzer

Published by Pearson

# Chapter P - Section P.2 - Exponents and Scientific Notation - Exercise Set - Page 30: 61

#### Answer

$\frac{-27b^{15}}{a^{18}}$

#### Work Step by Step

Start with the given expression: $(\frac{-15a^{4}b^2}{5a^{10}b^{-3}})^{3}$ Remove parentheses: $\frac{(-15)^3(a^4)^3(b^2)^3}{5^3(a^{10})^3(b^{-3})^3}$ Use power rule to simplify numerator and denominator: $\frac{-3375a^{12}b^{6}}{125a^{30}b^{-9}}$ Use quotient rule to simplify fraction: $-27a^{-18}b^{15}$ Use negative exponent rule to simplify completely: $\frac{-27b^{15}}{a^{18}}$

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