Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.2 - Exponents and Scientific Notation - Exercise Set: 55

Answer

$\frac{1}{16x^6}$

Work Step by Step

Start with given expression: $(4x^{3})^{-2}$ Apply the negative exponent rule: $\frac{1}{(4x^{3})^{2}}$ Remove the parentheses in the denominator: $\frac{1}{4^{2}\times (x^{3})^{2}}$ Simplify denominator using power rule: $\frac{1}{16x^6}$
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