## Precalculus (6th Edition) Blitzer

$\frac{1}{16x^6}$
Start with given expression: $(4x^{3})^{-2}$ Apply the negative exponent rule: $\frac{1}{(4x^{3})^{2}}$ Remove the parentheses in the denominator: $\frac{1}{4^{2}\times (x^{3})^{2}}$ Simplify denominator using power rule: $\frac{1}{16x^6}$