Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.2 - Exponents and Scientific Notation - Exercise Set: 105

Answer

$9\times10^{-3}$

Work Step by Step

$\frac{0.00072 \times 0.003}{ 0.00024}=\frac{7.2\times10^{-4}\times3\times10^{-3}}{2.4\times10^{-4}}=\frac{21.6\times10^{-7}}{2.4\times10^{-4}}=9\times10^{-3}$
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