Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.2 - Exponents and Scientific Notation - Exercise Set - Page 30: 109


$\frac{y}{16x^{ 8}z^{6}}$

Work Step by Step

$(2x^{-3}yz^{-6})(2x)^{-5}=\frac{(2x^{-3}yz^{-6})}{(2x)^{ 5}}=\frac{2y}{32x^{ 5}x^{3}z^{6}}=\frac{y}{16x^{ 8}z^{6}}$
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