Chapter P - Section P.2 - Exponents and Scientific Notation - Exercise Set - Page 30: 108

$$\frac{y^7}{x^8}$$

Work Step by Step

\begin{align} \frac{(xy^{-2})^{-2}}{(x^{-2}y)^{-3}} & = \frac{x^{-2}y^4}{x^6y^{-3}}\\ &= \frac{y^3y^4}{x^2x^6} \\ &= \frac{y^7}{x^8} \end{align}

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