Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.2 - Exponents and Scientific Notation - Exercise Set - Page 30: 108



Work Step by Step

\begin{align} \frac{(xy^{-2})^{-2}}{(x^{-2}y)^{-3}} & = \frac{x^{-2}y^4}{x^6y^{-3}}\\ &= \frac{y^3y^4}{x^2x^6} \\ &= \frac{y^7}{x^8} \end{align}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.