Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.6 - Conic Sections in Polar Coordinates - Exercise Set - Page 1031: 41


hyperbola, see graph

Work Step by Step

Step 1. Rewrite the given equation in standard form as $r=\frac{12}{4+5sin\theta}=\frac{3}{1+\frac{5}{4}sin\theta}$ Step 2. We can identify: $e=\frac{5}{4}\gt 1$, representing a hyperbola. Step 3. We can identify: $ep=3, p=\frac{12}{5}$ and the directrix as $y=\frac{12}{5}$ Step 4. We can graph the equation as shown in the figure.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.