Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.6 - Conic Sections in Polar Coordinates - Exercise Set - Page 1031: 35

Answer

See explanations.

Work Step by Step

Given a polar equation of the general form $r=\frac{a}{b+c\ sin\theta}$ or $r=\frac{a}{b+c\ cos\theta}$, divide $b$ from both the numerator and the denominator. We have $r=\frac{a/b}{1+c/b\ sin\theta}$ or $r=\frac{a/b}{1+c/b\ cos\theta}$. We can find the eccentricity as $e=\frac{c}{b}$.
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