## Precalculus (6th Edition) Blitzer

$32.39$ astronomical units (which is $\approx 3013$ million miles)
We have $r=\dfrac{1.069}{1+0.967 \sin \theta}$ or, $r=\dfrac{1.069}{1+0.967 \sin (\dfrac{3 \pi}{2})}$ (we use $\theta=\dfrac{3\pi}{2}$ for the maximum distance from the sun.) or, $r \approx 32.39$ astronomical units