## Precalculus (6th Edition) Blitzer

$4122$ miles and $162$ miles
We have $r=\dfrac{4090.76}{1-0.0076 \cos \theta}$ or, $r=\dfrac{4090.76}{1-0.0076 \cos (0)}$ (we use $\theta=0$ for the maximum distance from the center of the Earth.) or, $r \approx 4122$ miles We subtract the average radius of the Earth to get the distance from the surface of the Earth: $4122- 3960=162$ miles