Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.6 - Conic Sections in Polar Coordinates - Exercise Set - Page 1031: 29

Answer

$0.54$ astronomical units (which is $\approx51$ million miles)

Work Step by Step

We have $ r=\dfrac{1.069}{1+0.967 \sin \theta}$ or, $ r=\dfrac{1.069}{1+0.967 \sin (\dfrac{\pi}{2})}$ (we use $\theta=\pi/2$ for the shortest distance from the Sun.) or, $ r \approx 0.54$ astronomical units
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.