Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.2 - The Hyperbola - Exercise Set - Page 984: 97

Answer

See graph and explanations.
1585186801

Work Step by Step

Step 1. From the equation, we can identify the vertex as $(1,2)$ and axis of symmetry as $x=1$ Step 2. We can find x-intercepts as $x=1\pm\sqrt {\frac{2}{3}}$ or $x=1-\frac{\sqrt 6}{3}$ and $x=1+\frac{\sqrt 6}{3}$ Step 3. We can find the y-intercept as $y=-3(0-1)^2+2=-1$ Step 4. We can graph the equation as shown in the figure.
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