Answer
amplitude $|A|=3$, period $p= 2\pi$, and phase shift $\phi=-\pi$
Work Step by Step
Step 1. Given $y=3\ sin(x+\pi)$, we can determine the amplitude as $|A|=3$, period as $p=\frac{2\pi}{1}=2\pi$, and phase shift as $\phi=-\pi$
Step 2. We can graph one period ($2\pi$) of the function as shown in the figure.
