Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.2 - The Hyperbola - Exercise Set - Page 984: 78

Answer

See graph and explanations.
1585183601

Work Step by Step

Step 1. Graph equations $\frac{x^2}{4}-\frac{y^2}{9}=1$ (red) and $\frac{x^2}{4}-\frac{y^2}{9}=-1$ (blue) as shown in the figure. Step 2. We can see that they have different transverse axes with exchanged $a, b$ values.
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