Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.2 - The Hyperbola - Exercise Set - Page 984: 93

Answer

$78\ gal$

Work Step by Step

Step 1. Based on the given conditions, we have $W(t)=kt$, where $k$ is a constant. Step 2. At $t=5\ min$, we have $W(5)=30\ gal$. Thus $30=5k$ and $k=6\ gal/min$ Step 3. At $t=13\ min$, we have $W(13)=6(13)=78\ gal$
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