Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.2 - The Hyperbola - Exercise Set - Page 984: 80

Answer

See graph and explanations.
1585957507

Work Step by Step

Step 1. Graph $\frac{x^{2}}{16}-\frac{y^{2}}{9}=1$ (red) and $\frac{x\left|x\right|}{16}-\frac{y\left|y\right|}{9}=1$ (blue) as shown in the figure. Step 2. The two curves are not identical because when $x\lt0, x^2\ne x|x|$, and when $y\lt0, y^2\ne y|y|$ resulting in the two curves departing in some regions.
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