Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.2 - The Hyperbola - Exercise Set - Page 982: 59

Answer

see graph; $(0,-3)$ and $(0,3)$

Work Step by Step

Step 1. Given equations $9x^2+y^2=9$ and $y^2-9x^2=9$, we can graph both equations as shown in the figure. Step 2. We can identify two intersection points $(0,-3)$ and $(0,3)$ as solutions to the system. Step 3. Check the solutions with the first equation: we have $9(0)^2+(-3)^2=9$ and $9(0)^2+(3)^2=9$ Step 4. Check the solutions with the second equation: we have $(-3)^2-9(0)^2=9$ and $(3)^2-9(0)^2=9$
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