Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.2 - The Hyperbola - Exercise Set - Page 982: 37


asymptotes: $y=\pm\frac{1}{2}(x-1)-2$ foci: $(1,-2\pm2\sqrt {5})$

Work Step by Step

Step 1. From the given equation $\frac{(y+2)^2}{4}-\frac{(x-1)^2}{16}=1$, we have $a=2, b=4, c=\sqrt {a^2+b^2}=2\sqrt {5}$ centered at $(1,-2)$ with a vertical transverse axis. Step 2. We can find the vertices as $(1,-4),(1,0)$ and asymptotes as $y+2=\pm\frac{a}{b}(x-1)$ or $y=\pm\frac{1}{2}(x-1)-2$ Step 3. We can graph the equation as shown in the figure with foci at $(1,-2\pm2\sqrt {5})$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.