Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.2 - The Hyperbola - Exercise Set - Page 982: 54

Answer

see graph; domain $[-5,5]$, range $[-2,2]$

Work Step by Step

Step 1. From the given equation $\frac{(x)^2}{25}+\frac{(y)^2}{4}=1$, we have $a=5, b=2, c=\sqrt {a^2-b^2}=\sqrt {21}$ centered at $(0,0)$ with a horizontal major axis. Step 2. We can find the vertices as $(\pm5,0),(0,\pm2)$, foci as $(\pm\sqrt {21},0)$ Step 3. We can graph the equation as shown in the figure with domain $[-5,5]$ and range $[-2,2]$
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