Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.2 - The Hyperbola - Exercise Set - Page 982: 53

Answer

see graph; domain $[-3.3]$, range $[-4,4]$
1585157990

Work Step by Step

Step 1. From the given equation $\frac{(x)^2}{9}+\frac{(y)^2}{16}=1$, we have $a=4, b=3, c=\sqrt {a^2-b^2}=\sqrt {7}$ centered at $(0,0)$ with a vertical major axis. Step 2. We can find the vertices as $(0,\pm4),(\pm3,0)$, foci as $(0,\pm\sqrt {7})$ Step 3. We can graph the equation as shown in the figure with domain $[-3.3]$ and range $[-4,4]$
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