## Precalculus (6th Edition) Blitzer

see graph; domain $(-\infty,-5]\cup[5,\infty)$, range $(-\infty,\infty)$
Step 1. From the given equation $\frac{(x)^2}{25}-\frac{(y)^2}{4}=1$, we have $a=5, b=2, c=\sqrt {a^2+b^2}=\sqrt {29}$ centered at $(0,0)$ with a horizontal transverse axis. Step 2. We can find the vertices as $(\pm5,0)$, foci as $(\pm\sqrt {29},0)$, and asymptotes as $y=\frac{b}{a}(x)$ or $y=\pm\frac{2}{5}(x)$ Step 3. We can graph the equation as shown in the figure with domain $(-\infty,-5]\cup[5,\infty)$ and range $(-\infty,\infty)$