Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.2 - The Hyperbola - Exercise Set - Page 982: 52

Answer

see graph; domain $(-\infty,-5]\cup[5,\infty)$, range $(-\infty,\infty)$
1585157641

Work Step by Step

Step 1. From the given equation $\frac{(x)^2}{25}-\frac{(y)^2}{4}=1$, we have $a=5, b=2, c=\sqrt {a^2+b^2}=\sqrt {29}$ centered at $(0,0)$ with a horizontal transverse axis. Step 2. We can find the vertices as $(\pm5,0)$, foci as $(\pm\sqrt {29},0)$, and asymptotes as $y=\frac{b}{a}(x)$ or $y=\pm\frac{2}{5}(x)$ Step 3. We can graph the equation as shown in the figure with domain $(-\infty,-5]\cup[5,\infty)$ and range $(-\infty,\infty)$
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