Answer
See one possible answer below.
Work Step by Step
Step 1. Given $y=x^2+6$, we can assume $x=t$ and thus $y=t^2+6$
Step 2. We can also assume $x=\sqrt 6\ tan(t)$ and thus $y=(\sqrt 6\ tan(t))^2+6=6tan^2t+6=6sec^2t$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 9 - Review Exercises - Page 1036: 58
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
