Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Review Exercises - Page 1036: 37


$x^2=9691y$; $58\ ft$

Work Step by Step

Step 1. Using the figure given in the exercise, we can write the general form of the parabola as $x^2=4py$ Step 2. As the point $(1750,316)$ is on the parabola, we have $1750^2=4p(316)$, which gives $4p=\frac{1750^2}{316}\approx9691$. Thus the parabola is $x^2=9691y$ Step 3. To find the height at $x=1750-1000=750\ ft$, we have $y=\frac{750^2}{9691}\approx58\ ft$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.