Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Review Exercises - Page 1036: 54

Answer

$(y-1)^2=\frac{1}{4}x$; see figure.
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Work Step by Step

Step 1. Using the second equations, we have $y=t+1$ or $t=y-1$ Step 2. Substituting into the first equation, we have $x=4(y-1)^2$, which gives $(y-1)^2=\frac{1}{4}x$ indicating a parabola that opens to the right with a vertex at $(0,1)$. Step 3. We can graph the above equation as shown in the figure.
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