## Precalculus (6th Edition) Blitzer

$(y-1)^2=\frac{1}{4}x$; see figure.
Step 1. Using the second equations, we have $y=t+1$ or $t=y-1$ Step 2. Substituting into the first equation, we have $x=4(y-1)^2$, which gives $(y-1)^2=\frac{1}{4}x$ indicating a parabola that opens to the right with a vertex at $(0,1)$. Step 3. We can graph the above equation as shown in the figure.