## Precalculus (6th Edition) Blitzer

The matrix is, $\left[ \begin{matrix} 1 \\ -1 \\ 2 \\ -2 \\ 0 \\ \end{matrix} \right]$
The augmented matrix for the provided system of equations is: $\left[ \begin{matrix} 2 & -2 & 3 & -1 & 0 & 12 \\ 1 & 2 & -1 & 2 & -1 & -7 \\ 1 & 0 & 1 & 1 & -5 & 1 \\ -1 & 1 & -1 & -2 & -3 & 0 \\ 1 & -1 & 0 & -1 & -1 & 4 \\ \end{matrix} \right]$ Follow the steps given below to solve the provided equations: Step 1: Open the Ti-83 calculator and press the $\left[ 2\text{nd} \right]$ key then press $\left[ \text{MATRIX} \right]$ key. Step 2: Press $\left[ 2\text{nd} \right]$ key, and ${{x}^{-1}}$ then press $\left[ \text{MATRIX} \right]$ key. Use right arrow and select $\left[ \text{EDIT} \right]$. Enter $\left[ 1 \right]$ for matrix $\left[ \text{A} \right]$ then enter the order of the matrix then press $\left[ \text{ENTER} \right]$ key and enter the elements into the matrix. Step 3: Press $\left[ 2\text{nd} \right]$ and $\left[ \text{MATRIX} \right]$ key then go to “MATH” and select “rref (“. Step 4: Press $\left[ \text{ENTER} \right]$, then press $\left[ 2\text{nd} \right]$ key and 1, then press $\left[ \text{ENTER} \right]$ key. The resulting matrix is: $\left[ \begin{matrix} 1 & 0 & 0 & 0 & 0 & 1 \\ 0 & 1 & 0 & 0 & 0 & -1 \\ 0 & 0 & 1 & 0 & 0 & 2 \\ 0 & 0 & 0 & 1 & 0 & -2 \\ 0 & 0 & 0 & 0 & 1 & 0 \\ \end{matrix} \right]$ Hence, the solution is: $\left[ \begin{matrix} 1 \\ -1 \\ 2 \\ -2 \\ 0 \\ \end{matrix} \right]$ The solution of the provided system is, $\left[ \begin{matrix} 1 \\ -1 \\ 2 \\ -2 \\ 0 \\ \end{matrix} \right]$